Chem Titrations

Question

In a certain reaction, 17.2 mL of 0.600 M H2SO4 is fully neutralized by 19.4 mL of NaOH of unknown molarity.

Calculate the molarity of the NaOH.

a. 0.266 M

b. 0.532 M

c. 1.35 M

d. 1.06 M

Answer 1

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O .. balanced equation

moles H2SO4 present = 17.2 ml x 1 L/1000 ml x 0.600 mol/L = 0.01032 mols

moles NaOH required for full neutralization = 0.01032 mol H2SO4 x 2 mol NaOH/mol H2SO4 = 0.02064 mol

Molarity of NaOH = mol/L = 0.02064 mol / 0.0194 L = 1.06 mol/L = 1.06 M