J.R. S. answered 10/22/22
Ph.D. University Professor with 10+ years Tutoring Experience
HBr(aq) + NaOH(aq) ==> NaBr(aq) + H2O(l) ... balanced equation
Because we are given the amounts of BOTH reactants, we must first determine which reactant is limiting. One way to do this is to divide the moles of each reactant by the corresponding coefficient in the balanced equation. Whichever result is less will identify the limiting reactant.
For HBr: 3.24 g x 1 mol HBr / 80.9 g = 0.0400 moles HBr
For NaOH: 2.9 g x 1 mol NaOH / 40 g = 0.0725 mols NaOH
Since both have coefficients of 1, the HBr is the limiting reactant.
Now, use the moles of HBr to calculate the mass of NaBr:
0.0400 mols HBr x 1 mol NaBr / mol HBr x 103 g / mol NaBr = 4.1 g NaBr (2 sig. figs.)