P(Recover) = 0.8, where the probability is a success.
n = 20 patients in a group
X ~ Binomial (20, 0.8)
E(X) = np = (20)(0.8) = 16
V(X) = npq = (20)(0.8)(0.2) = 3.2 (Note: q is the failure probability, where q = 1 - p)
The expected number of patients who recovered from the disease is 16 and the variance is about 3.2.