Let λ = 15.6 received in one hour, where X ~ Poisson (λ). λ is also a mean (average).
The mean is the same as the variance according to the textbook such as μ = σ2. The standard deviation is the square root of the variance such as σ = √σ2.
Variance: σ2 = 15.6
Standard Deviation: σ = √15.6 ≈ 3.95