A chemist adds 85ml of a 5.38 mol/l silver nitrate solution to a reaction flask. Calculate the millimoles of silver nitrate the chemist has added to the flask.

Answer 1

Conversions:

85 ml AgNO₃ x 1 L / 1000 ml x 5.38 mol / L x 1000 mmol / mol = 457 mmoles AgNO₃ = 460 mmoles (2 s.f.)