Equilibrium Question

Question

For the reaction

2NH3​(g)+2O2​(g)N2​O(g)+3H2​O(g)

the initial mixture contains 7.45 mol NH₃ and 6.50 mol O₂. At equilibrium, 1.50 mol of N₂O gas are found.

How many moles of NH₃, O₂, and H₂O are present at equilibrium? Be sure to give your answers to two decimal places.

 ____ mol NH₃   

 ____ mol O₂   

 ____ mol H₂O   

Answer 1

Set up an ICE table

2NH₃​(g) + 2O2​(g <===> N₂​O(g) + 3H₂​O(g)

4.75.............6.5..................0.................0..........Initial

-2x..............-2x...................+x...........................Change

4.75-2x......6.5-2x................x............................Equilibrium

x = 1.50

@equilibrium, we have ...

4.75 - 2x = 4.75 - 3 = 1.75 mols NH3

6.5 - 2x = 6.5 = 3 = 3.50 mols O2

3x = 3*1.50 = 4.50 mols H2O