How many grams of NO2 are needed to form 86.0 g of HNO3

Answer 1

You need to write the balanced equation for the reaction taking place:

3NO₂ + H₂O ==> 2HNO₃ + NO ... balanced equation

Then use dimensional analysis to get the answer:

86.0 g HNO₃ x 1 mol HNO₃ / 63.0 g x 3 mol NO₂ / 2 mol HNO₃ x 46.0 g / mol NO₂ = 94.2 g NO₂ needed