J.R. S. answered 10/18/22
Ph.D. University Professor with 10+ years Tutoring Experience
Do this the same way as your previous question which I have answered. Just change the amount of HCl being added from 0.05 mol to 0.04 mol.
J.R. S. answered 10/18/22
Ph.D. University Professor with 10+ years Tutoring Experience
Do this the same way as your previous question which I have answered. Just change the amount of HCl being added from 0.05 mol to 0.04 mol.
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