Mark M. answered 10/16/22
Retired Math prof with teaching and tutoring experience in trig.
Recall that cos2β + sin2β = 1. So, cos2β = 1 - sin2β.
Therefore, 5cos2β - 5sin2β = 5(1 - sin2β) - 5sin2β= 5 - 10sin2β
Caitlyn R.
asked 10/16/22Verify the identity. (Simplify at each step.)
Mark M. answered 10/16/22
Retired Math prof with teaching and tutoring experience in trig.
Recall that cos2β + sin2β = 1. So, cos2β = 1 - sin2β.
Therefore, 5cos2β - 5sin2β = 5(1 - sin2β) - 5sin2β= 5 - 10sin2β
Raymond B. answered 10/16/22
Math, microeconomics or criminal justice
5cos^2B - 5sin^2B =5 -10sin^2B
divide by 5
cos^2B -sin^2B =1-2sin^2B
cos^2B + sin^2B = 1 which is a version of the Pythagorean Theorem
(a/h)^2 + (o/h)^2 = 1^2 where a=adjacent side, o=opposite side, 1 = hypotenuse on a unit circle
or you'll find a hundred+ proofs of the Pythagorean Theorem on line, including one by deceased former President James A. Garfield, a geometric proof.
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