What is the enthalpy change, delta hcomb, per mole of methanol

Question

In a balanced thermochemical equation of the combustion of methanol gas: 2CH₃OH + 3O₂ = 2CO₂ + 4H₂O + 1452kJ

Answer 1

2CH₃OH + 3O₂ ==> 2CO₂ + 4H₂O + 1452kJ

The reaction, as written, is for 2 moles of methanol (CH₃OH)

Therefore, the ∆H_combustion per mole = 1452 kJ / 2 mol = 726 kJ / mole