Algebra! Can anyone help me?

Question

If 4x - y = 2y + 8 and x + 6y = 5, what is the value of x?

Answer 1

4x-3y=8

x+6y=5

x=5-6y

4(5-6y)-3y=8

-27y=8 -20= -12

y=12/27= 4/9

x=5-6(4/9)=21/9=7/3

x=7/3, y=4/9

4(7/3)-3(4/9)

= 38/3+12/9

=28/3-4/3 =24/3 = 8

Answer 2

4x - y = 2y + 8 combine the y's

4x - 3y = 8

x + 6y = 5 Need adjust 2nd eqn so can elim x term

-4(x + 6y = 5) → -4x - 24y = -20

4x - 3y = 8

-4x - 24y = -20 Add them

-27y = -12 y = 12/27 Substitute 12/27 for y into either original eqn to find x.

Could also use substitution: x = 5 - 6y → 4(5 - 6y) - y = 2y + 8

20 - 24y - y = 2y + 8

-27y = -12

y = 12/27