Unbalanced equation: NO (g) + H2 (g) N2 (g) + H2O (l) In one reaction, 63.4 g of H2O is produced. What amount (in mol) of H2 was consumed? What mass (in grams) of N2 is produced?

Answer 1

First, balance the equation:

2NO(g) + 2H₂(g) ==> N₂(g) + 2H₂O(l) ... balance equation

Use dimensional analysis along with the stoichiometry of the balanced equation to answer the question:

63.4 g H₂O x 1 mol H₂O/18 g H₂O x 2 mol H₂ / 2 mol H₂O = 3.52 moles H₂

63.4 g H₂O x 1 mol H₂O/18 g H₂O x 1 mol N₂ / 2 mol H₂O x 28 g N₂ / mol N₂ = 49.3 g N₂