How many ions are formed during the dissociation of 500 molecules of carbonic acid, if it dissociates in the first degree by 20%, and in the second degree by 1%?

Question

dissociation’s

Answer 1

Carbonic acid = H₂CO₃

Dissociation of H₂CO₃:

H₂CO₃ ==> H⁺ + HCO₃^- ... 1st dissociation

HCO₃^- ==> H⁺ + CO₃^2- ... 2nd dissociation

Now, if I understand you question correctly (it is somewhat vague in the way it is worded), then ...

20% dissociation of 500 molecules H₂CO₃ = 100 H⁺ ions + 100 HCO₃^- ions

1% dissociation of 100 molecules HCO₃^- = 1 H⁺ ion + 1 CO₃^2- ion

Total number of molecules 100 + 100 + 1 + 1 = 202 ions