What is the pressure (in torr) of 2.10 mol of gas in a 7.00 L container at 65.0 °C?

Answer 1

As in your previous question, use the ideal gas law PV = nRT and solve for P

P = nRT / V = (2.10 mol)(0.0821 Latm/Kmol)(338K) / 7.00L

P = 8.32 atm

The question wants this in torr so convert

8.32 atm x 760 torr / atm = 6323 torr