What volume in liters would 20.0 moles of sulfur dioxide occupy at 85.1 °C with a pressure of 2.00 bar? R = 0.08314 L･bar/mol･K.

Answer 1

Ideal gas law: PV = nRT

P = pressure in bar = 2.00 bar

V = volume in L = ?

n = moles = 20.0

R = gas constant = 0.08314 Lbar/Kmol

T = temperature in Kelvin = 85.1ºC + 273 = 358.1K

Solving for V, we have ...

V = nRT / P = (20.0)(0.08314)(358.1) / 2.00

V = 298 L (3 sig. figs.)