what is the answer?

Question

SubstanceSpecific heat J/(g · °C)
lead	0.128
silver	0.235
copper	0.385
iron	0.449
aluminum	0.903

The temperature of a sample of lead increased by 24.3 °Cwhen 255 J of heat was applied.

What is the mass of the sample?

𝑚=

Answer 1

Kayla: You shouldn't post so many questions all at once and with the same title "what is the answer?" because it becomes obvious to us tutors that we are now just doing your homework. That's a Wyzant "no no". I just answered a question about final temperature of gold, silver and water, and I'll show you this one also. But I'm doubtful you'll get a great response from others.

q = mC∆T

q = heat = 255 J

m = mass = ?

C = specific heat = 0.128 J/gº

∆T = change in temperature = 24.3º

Solve for m (mass) ...

m = q / (C)(∆T)

m = 255 J / (0.128 J/gº)(24.3º0

m = 82.0 g (3 sig. figs.)