How many grams of CO2 can be absorbed when 0.250 kg LiOH reacts. 2LiOH + CO2 → Li2CO3 + H2O

Answer 1

2LiOH + CO₂ ==> Li₂CO₃ + H₂O ... balanced equation

molar mass LiOH = 23.95 g/mol

molar mass CO2 = 44 g/mol

1. moles LiOH present = 0.250 kg x 1000 g / kg x 1 mol / 23.95 g = 10.44 mols LiOH
2. moles CO₂ that can react = 10.44 mol LiOH x 1 mol CO₂ / 2 mol LiOH = 5.22 mols CO₂
3. grams CO₂ absorbed = 5.22 mol CO₂ x 44 g / mol = 230. g CO₂ (3 sig. figs.)