The plants growing is assumed to be independent of the other plants. This will result in a binomial distribution of 5 positives out of 6:
6C5p5(1-p)1 where the combination of 6 things 5 at a time is 6 and p = .75
Please consider a tutor. Take care.
Wesley D.
asked 10/10/22The plants growing is assumed to be independent of the other plants. This will result in a binomial distribution of 5 positives out of 6:
6C5p5(1-p)1 where the combination of 6 things 5 at a time is 6 and p = .75
Please consider a tutor. Take care.
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