J.R. S. answered 10/09/22
Ph.D. University Professor with 10+ years Tutoring Experience
2 Ce4+(aq) + H2O2(aq) + 2 H2O(l) ==> 2 Ce3+(aq) + O2(g) + 2 H3O+(aq)
mols Ce4+ used = 15.06 ml x 1 L / 1000 ml x 0.1375 mol / L = 0.002071 mols
mols H2O2 = 0.002071 mol Ce4+ x 1 mol H2O2 / 2 mol Ce4+ = 0.001036 mol H2O2
Concentration of H2O2 = 0.001036 mols / 0.0400 L = 0.02589 M (4 sig. figs.)
