given cos -3/8 and tan theta <0 find values of secant and tangent

Question

given cos -3/8 and tan θ <0 find the  values of secant and tangent

Answer 1

Greetings! Lets solve this shall we ?

So, we must find the trug functions secant and tangent given cosθ = -3/8 and tanθ < 0. Since we have cosine, we can find sine such that (-3)² + (x)² = (8)². Then, x = √(55) after solving for x. So, sinθ = √(55) / 3 to find tanθ and secθ. Let secθ be the reciprocal identity such that

secθ = (1/cosθ) = (1/(-3/8)) = -8/3.

Now, we can find tangent tanθ such that

tanθ = (sinθ/cosθ) = [(√(55)/3) / (-3/8)] = (√55/3)*(-8/3) = - √(55)/3

I hope this helped!