NiCl3 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.700 M NiCl3 solution.

Answer 1

Being a strong electrolyte, NiCl₃ will dissociate as follows:

NiCl₃ ==> Ni³⁺ + 3Cl^-

Note there are 3 Cl^- ions for every 1 Ni³⁺ ion

0.700 M NiCl₃ = 0.700 M Ni³⁺ and 3x0.700 = 2.10 M Cl^-