A horse is trotting at 2.52 m/s. How fast would it be going after 5.03 seconds if it has an acceleration of 2.5944 m/s^2?

Answer 1

We can use 2d kinematic equations to solve this question.

The equation we want is V_f = V_o + at

where V_f is the final velocity

V_o is the initial velocity

a is the acceleration

t is the time

So we can just input our numbers to get

V_f = 2.52 m/s + (2.5944 m/s²)(5.03s)

Just stick that in your calculator and you have your answer!