In the reaction 551.00 moles of copper (2)nitrate, how much product is produced of copper (2) oxide in grams, nitrogen oxide in grams, and molecular oxygen in grams?

Answer 1

Assuming the reaction in question is the thermal decomposition of copper(II) nitrate, we can address the question as follows:

2Cu(NO₃)₂ ==> 2CuO + 4NO₂ + O₂ ... balanced equation (nitrogen dioxide is formed, not nitrogen oxide)

mols CuO produced = 551.00 mol Cu(NO₃)₂ x 2 mol CuO / 2 mol Cu(NO₃)₂ = 551.00 mols CuO

mols NO₂ produced = 551.00 mol Cu(NO₃)₂ x 4 mol NO₂ / 2 mol Cu(NO₃)₂ = 1102 mols NO₂

mols O₂ produced = 551.00 mol Cu(NO₃)₂ x 1 mol O₂ / 2 mol Cu(NO₃)₂ = 275.5 mols O₂

If you want the grams of each product, simply multiply the moles x the molar mass of each.