What is the concentration?

Question

Write the balanced neutralization reaction that occurs between H2SO4 and KOH in aqueous solution.

Suppose 0.150 L of 0.490 M H2SO4 is mixed with 0.100 L of 0.300 M KOH. What concentration of sulfuric acid remains after neutralization?

concentration:

Answer 1

H₂SO₄(aq) + 2KOH(aq) ==> K₂SO₄(aq) + 2H₂O(l) ... balanced equation

moles H₂SO₄ used = 0.150 L x 0.490 mol / L = 0.0735 mols

moles KOH added = 0.100 L x 0.300 mol / L = 0.0300 mols

moles H₂SO₄ neutralized (reacted) = 0.0300 mol KOH x 1 mol H₂SO₄ / 2 mol KOH = 0.0150 mols

moles H₂SO₄ left over = 0.0735 mols - 0.0150 mols = 0.0585 mols

Final total volume of solution = 0.150 L + 0.100 L = 0.250 L

Concentration of H₂SO₄ = 0.0585 mol / 0.250 L = 0.234 M