What is the percent yield?

Question

Consider the reaction.

2Pb(s)+O2(g)⟶2PbO(s)

An excess of oxygen reacts with 451.4 g of lead, forming 352.5 g of lead(II) oxide. Calculate the percent yield of the reaction.

percent yield:

Answer 1

2Pb(s) + O2(g) ==> 2PbO(s) ... balanced equation

using dimensional analysis and the mole ratios in the balanced equation, we have ...

451.4 g Pb x 1 mol Pb / 207.2 g x 2 mol PbO / 2 mol Pb x 223.2 g PbO / mol = 486.3g PbO theoretical yld

Percent yield = actual yield / theoretical yield (x100%) = 352.5 g / 486.3 g (x100%) = 72.49% yield