2cscx+5=1 solve on the interval [0,2p)

Question

2cscx+5=1 solve on the interval [0,2π)

 

a) π/3, 5π/3

b) π/6, 5π/6

c) 2π/3, 4π/3

d)7π/6, 11π/6

 

 

 

2) 

 solve on the interval [0, 2π)

 

1+sin(theta)=(√3 +2)/2 

 

a) π/3, 5π/3

b) π/6, 5π/6

c) 2π/3, 4π/3

d)π/3, 2π/3

 

 

This isn't a question, but can you remind me of what cot, csc, and sec trig identities are?

Answer 1

2) 1+sinθ=(√3+2)/2

        sinθ=(√3+2)/2-1

        sinθ=(√3/2)+(2/2)-1

        sinθ=(√3/2)+1-1

        sinθ=√3/2

        θ=(pi)/3 and 2(pi)/3   d) is the answer

Answer 2

2cscx + 5 = 1

2cscx = -4

cscx = -2

1 / sinx = -2

sinx = -1/2

 

{7π/6, 11π/6}