If you combine 440.0 mL of water at 25.00 ∘C and 140.0 mL of water at 95.00 ∘C, what is the final temperature of the mixture? Use 1.00 g/mL as the density of water.

Answer 1

q = mCT

(440 g)(4.184 J/gº)(Tf - 25º) = (140 g)(4.194 J/gº)(95º-Tf)

440Tf - 11,000 = 13,300 - 140Tf

580Tf = 24,300

Tf = 41.9ºC