Cece G.

asked • 03/18/15

(sinx+1)(2sin^2x-3sinx-2)=0

Solve on the interval [0, 2π)

 

(sinx+1)(2sin^2x-3sinx-2)=0

 

a) x=2π, x=π/2,x=π/3

b)x=π, x=2π/3, x=5π/3

c) x=3π/2, x=7π/6, x=11π/6

d) x=2π, x=π/2, x=5π/4

 
 
Please explain in detail.  Step BY STEP.  I am so confused!!!  I don't know what to do.  Do we factor??
 
I begging you please show every little step because I am easily confused.  I need to learn this and I'm scared I never will.  Truly appreciated!!! 

1 Expert Answer

By:

Cece G.

Thank you so much!!  I understand now.  I truly appreciate it, Sir. 
Report

03/18/15

Jon P.

tutor
You're welcome!
Report

03/18/15

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.