Geometry homework

Question

T=5x+10

S=58°

U=11x+2

A=?

Answer 1

If A=Area = (1/2)(5x+10)(11x+2)sin58)=(1/2)(55x^2+120x+20)sin58

or maybe A=the side opposite 58 degrees. then

by law of cosines

A^2= (5x+10)^2+(11x+2)^2-2(55x^2+120x+20)cos58

58 is nearly 60

so maybe this is roughly an equilateral triangle. then

all 3 sides are about equal

A= 5x+10=11x+2

6x=8

x=4/3

A=20/3+10=50/3 = about 17

for each side