Calculate Kc at this temperature for the following reaction:

Question

The equilibrium constant, K_c, for the following reaction is 2.44×10^-2 at 596 K.

NH₄Cl(s) NH₃(g) + HCl(g)

Calculate K_c at this temperature for the following reaction:

NH₃(g) + HCl(g) NH₄Cl(s)

K_c =

Answer 1

NH₄Cl(s) <==> NH₃(g) + HCl(g) Kc = 2.44x10^-2

NH₃(g) + HCl(g) <==> NH₄Cl(s) Kc = ?

This is the reverse of the first reaction and so the Kc for this rxn is the inverse of that for the first rxn.

Kc = 1 / (2.44x10^-2)

Kc = 41.0