Calculate the concentration of C at equilibrium.

Question

Consider the given reaction.

A(aq)+B(s)↽−−⇀C(aq) 𝐾=9.40

Suppose 10.9 mol A reacts with excess B in 6.45 L of solution. Calculate the concentration of C at equilibrium.

Answer 1

Converting 10.9 mol A to concentration in units of M, we have 10.9 mols / 6.45 L = 1.69 M

A(aq) +B(aq) <===> C(aq)

1.69.....1.69....................0..........Initial

-x...........-x..................+x.........Change

1.69-x....1.69-x.............x...........Equilibrium

K = [C] / [A][B]

9.40 = x / (1.69-x)²

Solve for x and that will be the [C] @ equilibrium