J.R. S. answered 09/29/22
Ph.D. University Professor with 10+ years Tutoring Experience
A(aq) <===> B(aq) K = 2.03x10-6
5.30..............0.......Initial
-x.................+x......Change
5.30-x...........x.......Equilibrium
K = [B] / [A]
2..03x10-6 = x / 5.30-x
3.83x10-7 - 2.03x10-6x = x
[B] @ equilibrium = 3.83x10-7 M