Calculate the solubility product, 𝐾spKsp, for SrF2SrF2.

Question

In a saturated aqueous solution of SrF2SrF2, the strontium ion concentration is 8.55×10−48.55×10−4 M and the fluoride ion concentration is 1.71×10−31.71×10−3 M. Calculate the solubility product, 𝐾spKsp, for SrF2SrF2.

Answer 1

SrF₂(s) <==> Sr²⁺(aq) + 2F^-(aq)

Ksp = [Sr²⁺][F-]² = (8.55x10^-4)(1.71x10^-3)²

Ksp = 2.50x10^-9