Stat question 9

Question

The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 35 liters, and standard deviation of 2.1 liters.

A) What is the probability that daily production is less than 31.9 liters? Use technology (not tables) to get your probability.

Answer=(Round your answer to 4 decimal places.)

B) What is the probability that daily production is more than 34.3 liters? Use technology (not tables) to get your probability.

Answer=(Round your answer to 4 decimal places.)

Answer 1

P(X < 31.9) = P(Z<(31.9-35)/2.1) = P(Z<-1.476) = 0.0699

P(X >34.3) = P(Z>(34.3-35)/2.1) = P(Z>-0.333) = 1 - P( Z < -0.333) = 1 - 0.3694 = 0.6306