J.R. S. answered 09/21/22
Ph.D. University Professor with 10+ years Tutoring Experience
∆E = RH (1/nf2 - 1/ni2)
∆E = change in energy = ?
RH = -2.179x10-18 J
nf = final energy level = 2
ni = initial energy level = 7
∆E = -2.179x10-18 J (1/4 - 1/49) = -2.179x10-18 J (0.2296)
∆E = - 5.00x10-19 J (negative value since falling from high energy to low energy level)