J.R. S. answered 09/21/22
Ph.D. University Professor with 10+ years Tutoring Experience
I2 <==> 2I ... fast
H2 + 2I ==> 2HI ... slow
(1). H2 + I2 ==> 2HI ... overall
(2). I
(3). Rate = k[H2][I]2 based on the slow step, BUT I is an intermediate and intermediates cannot appear in the rate law, so we need some manipulations:
From the fast step, we can write k1[I2] = k-1[I]2
Solving for [I]2 we have [I]2 = k1/k-1 [I2]
Substituting this into the rate law Rate = k[H2][I]2 we have ...
Rate =k[H2][ k1/k-1 [I2]
Combining rate constants we have our final rate law as ...
Rate = k'[H2][I2]