How much energy (in calories) is required to raise 2.000kg water from 35.00C to 71.000 C. (specific heat of water 1.0000cal/gC

Answer 1

q = mC∆T

q = heat = ?

m = mass = 2.000 kg x 1000 g / kg = 2000. g (4 s.f.)

C = specific heat = 1.0000 cal / gº (5 s.f.)

∆T = change in temperature = 71.000º - 35.00 = 36.00º (4 s.f.)

Solving for q ...

q = (2000. g)(1.0000 cal/gº)(36.00º)

q = 72.00 cal (4 sig. figs.)