1) t = (x-bar - µ0) / (s/√n) = (1.2 - 1) / (.2/√9) = 3
df - n-1 = 8
p-value = P(t ≥ 3 or t ≤ -3) = 0.017
2) Since our p-value of 0.017 is less than ∝ = 0.05, we would reject the null hypothesis. This means that we could make a Type I error - we conclude that the population mean is not equal to 1 when it actually is equal to 1.
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