J.R. S. answered 09/16/22
Ph.D. University Professor with 10+ years Tutoring Experience
Doubling [N2O3] from 0.1 M to 0.2 M also doubles the rate from 0.540 to 1.08.
Tripling the [N2O3] from 0.1 M to 0.3 M also triples the rate from 0.540 to 1.60.
This behavior tells us that the reaction is FIRST order in [N2O3].
The rate law for this first order reaction is ..
Rate = k[N2O3]
To find the value of k, simply use the data from the table and solve for k:
0.540 M/s = k [ 0.100 M]
k = 0.540 M/s / 0.100 M
k = 5.4 s-1