How many joules of heat are required to heat 35.1 g of isopropyl alcohol from the prevailing room temperature,21.2 degrees Celsius, to its boiling point, 82.4 degrees Celsius?

Answer 1

To answer this question, we need to know the specific heat for liquid isopropyl alcohol (IPA). Looking it up I find it to be 2.6 J/gº

Now we use q = mC∆T to find the amount of heat needed:

q = heat = ?

m = specific heat = 35.1 g

C = specific heat = 2.6 J/gº

∆T = change in temperature = 82.4º - 21.2º = 61.2º

Solving for q we have ...

q = (35.1 g)(2.6 J/gº)(61.2º)

q = 5585 J = 5590 J (3 sig. figs.)