xavg = sum from x = 0 to 3 of xp(x) = 0(.05)+1(.3)+2(.3)+3(.35) = 2.25
variance = sum from x = 0 to 3 of (x-xavg)2p(x)
= .05(-2.25)2 +(-1.25)2(.3)+(-.252(.3)+(1.252(.35) = 1.29
stand. dev = sqrt(var) = 1.135
Monem S.
asked 09/15/22x | P(x) |
0 | 0.05 |
1 | 0.3 |
2 | 0.3 |
3 | 0.35 |
Find the standard deviation of this probability distribution. Give your answer to at least 2 decimal places
xavg = sum from x = 0 to 3 of xp(x) = 0(.05)+1(.3)+2(.3)+3(.35) = 2.25
variance = sum from x = 0 to 3 of (x-xavg)2p(x)
= .05(-2.25)2 +(-1.25)2(.3)+(-.252(.3)+(1.252(.35) = 1.29
stand. dev = sqrt(var) = 1.135
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