Nick P. answered 09/15/22
Mathematics Student at Northeastern University
To solve this question, you need to find y(t), which actually isn't that difficult.
The biggest challenge is that you need to integrate dy/dt, which might seem challenging, but not if you remember to separate first, and integrate second.
$\frac{dy}{dt} = 0.2y$ is the same as $\frac{1}{.2y} dy = dt$.
If we integrate both sides, we get
$ln(.2y) = t + C$, for some constant $C$.
Remember that y is really the function y(t). So, if we solve for y in the above equation, we actually get just what we want!
Can you take it from here? (Hint: Remember that to get rid of the log on the left, you can exponentiate the entire equation! And then use the initial condition to find C)