Solve the differential equation. dy/dx=(3y^2)/(√x), y(1)=1/64 y(x)=? 1 64 y ( x ) =

Answer 1

dy/y² = 3dx/x^1/2; ∫dy/y² = 3∫dx/x^1/2; - 1/y = 6x^1/2 + C; - 64 = 6 + C; C = - 70; - 1/y = 6x^1/2 - 70;

y(x) = 1/(70 - 6x^1/2)