Yefim S. answered 09/15/22
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Math Tutor with Experience
du/dt = e5u·e2t; ∫e-5udu = ∫e2tdt; - e-5u/5 = e2t/2 + C; - e-80/5 = 1/2 + C ; C = -1/2 - 1/(5e80)
e2t/2 + e-5u/5 = 1/2 + e-80/5
Jasim C.
asked 09/14/22
Yefim S. answered 09/15/22
Math Tutor with Experience
du/dt = e5u·e2t; ∫e-5udu = ∫e2tdt; - e-5u/5 = e2t/2 + C; - e-80/5 = 1/2 + C ; C = -1/2 - 1/(5e80)
e2t/2 + e-5u/5 = 1/2 + e-80/5
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