
Yefim S. answered 09/15/22
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∫xdx = 9∫∫dt; x2/2 = 9t + C;; 25/2 = C; x2/2 = 5t + 12.5; x(t) = ±(19t + 25)1/2
Jasim C.
asked 09/14/22Yefim S. answered 09/15/22
Math Tutor with Experience
∫xdx = 9∫∫dt; x2/2 = 9t + C;; 25/2 = C; x2/2 = 5t + 12.5; x(t) = ±(19t + 25)1/2
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