J.R. S. answered 09/14/22
Ph.D. University Professor with 10+ years Tutoring Experience
Molar mass C2HF3O2 = 114 g / mol
Atomic mass fluorine (F) = 19.0 g / mol
Each mol C2HF3O2 contains 3 mols F or 3 x 19.0 g = 57 g F
Let's convert that to percent F
57 g / 114 g (x100%) = 50%
Now we can find the mass of C2HF3O2 knowing that it contains 53.7 g F
53.7 g / x g = 0.50
x = 107.4 g = 107 g (3 sig. figs.)