How do you find the volume and thickness of an aluminum foil when you only have the lenght, width and mass

Question

The lenght is 15 cm, the width is 12 cm and the mass is 1.02 g

Answer 1

You must use the density which is a property that you can look up. If you google "density of aluminum foil in g/cm3", the search shows it as 2.71 g/cm³.

(1.02 g)/(2.71 g.cm³) = 0.3764 cm³ = (rounded) 0.38 cm³

So that is the volume.

The thickness is the volume/(length•width) = (0.3764 cm³)/[(15 cm)•(12 cm)] = 0.0021 cm