releasing 31.91 g of C2H2F3Cl in the air every week. If the leak is not fixed, how many kilograms of fluorine will be released into the air over 6 months? Assume there are 4 weeks in a month.

Answer 1

Molar mass C₂H₂F₃Cl = 118.5 g / mol

31.91 g C₂H₂F₃Cl x 1 mol / 118.5 g = 0.2698 mols C₂H₂F₃Cl released per week

6 months x 4 weeks / month x 0.2698 mols / week = 6.475 mols C₂H₂F₃Cl released in 6 months

6.475 mols C₂H₂F₃Cl x 3 mols F / mol C₂H₂F₃Cl x 19 g F / mol F = 369.1 g F released in 6 months