J.R. S. answered 09/08/22
Ph.D. University Professor with 10+ years Tutoring Experience
Zn(s) + CuSO4(aq) ==> ZnSO4(aq) + Cu(s) ... Eº = 1.05 V
∆Gº = -nFEº = -2 mol e- x 96485C/mol e- x 1.05 V = 202,619 CV = 202,619 J = 2.0x105 J per mol of Zn
Atomic mass Zn = 65.4 g / mol
15.0 g Zn x 1 mol / 65.4 g = 0.229 mols Zn
Maximum work = 0.229 mols x 2.0x105 J/mol = 45,800 J