Help me solve this!!!

Question

The given solubility of X at 100ºC in water is 17.0 g/100 mL of water and the other given solubility of X at 0ºC in water is 3.5 g/100 mL of water. How many mL of boiling water would be required to dissolve 26g of X? If that solution was then cooled down to 0ºC, how many grams of X could then crystallize out? What would be the maximum yield recovery for X?

Answer 1

Boiling water is assumed to be at 100ºC so the solubility is 17.0 g/100 ml

26 g x 100 ml / 17.0 g = 1.53 mls = 1.5 mls of boiling water needed

Solubility at 0º is 3.5 g/100 ml

26 g - 3.5 g = 22.5 g = 23 g of X have crystallized

Maximum yield recovery = 23 g / 26 g (x100%) = 88.5% = 89%